Tomcat Classpath -


जब मैं अपने टॉमकैट में निम्नलिखित jsp चलाता हूँ ... 

  & lt; html & gt; & Lt; शीर्ष & gt; & Lt; meta http-equiv = "सामग्री-प्रकार" सामग्री = "पाठ / html; वर्णसेट = आईएसओ -885 9 -1" & gt; & Lt; title & gt; शीर्षक यहां सम्मिलित करें & lt; / title & gt; & Lt; / head & gt; & LT; बॉडी & gt; पहले: cp = & LT;% = System.getProperty ( "java.class.path")% & gt; & Lt; / body & gt; & Lt; / html & gt;

मुझे यह आउटपुट मिलता है ...

इससे पहले: cp = C: \ apache-tomcat-6.0.24 \ bin \ bootstrap.jar; C: \ Program फ़ाइलें \ जावा \ jdk1.6.0_19 \ lib \ tools.jar

मैं सी कैसे कर सकता हूँ: \ Myfolder \ project यहाँ दिखाई देता है ...? मैं अपने tomcat6 वर्ग पथ को कैसे इस फ़ोल्डर को सेट कर सकता हूँ ..

Kaddy

आप catalina.bat (या .sh) को संपादित कर सकते हैं उस। लेकिन अगर आप बस कक्षा में कुछ जार डालते हैं, तो उन्हें \ lib

संपादित करें: इसे करने का सबसे अच्छा तरीका catalina.bat को संपादित नहीं करना है, लेकिन इसके बाद setenv.bat बनाने के लिए है और सभी परिवर्तन आपको CLASSPATH वेरिएबल में करें जो आपको चाहिए।


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