java - Defining database independent JPA object uid -


It turns out that the following example works when using mysql 5.x, but this is not when an oracle 10g database.

@ ID @ Generated Values ​​(strategy = GenerationType.IDENTITY) @ Column (

name = "id") Private long ID;

I tested it in Hibernate and the following exception occurs when Oracle is used: 

  org.hibernate.MappingException: Colloquial Identification Generation does not support    
 
 
 Use a database table to generate an identifier Portable way.  
  @ ID = Generated Values ​​(strategy ================================= ==========

If you are using schema generation then the provider will create the default table; If not, then you must specify an existing table: 

  @TableGenerator (name = "invabab", table = "id_ng", pkColumnName = "id_NAME", valueColumnName = "ID_VAL", pkColumnValue = "INV_GEN") @ ID @ Generated Values ​​(generator = "invoice") @column (name = "id") Private long ID;


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