Pattern matching using python -


How to match the dictionary after "answer" and "nonanswer" in the word below 

  opt_dict = ({'answer1': 1, 'answer13': 12, 'answer11': 6, 'answer5': 5, 'nonanswer12': 1, 'nonanswer11': 1, Opt_dict : Ii opt_dict: logging.debug (ii) for logging if opt_dict: if, 'nonanswer4': 1, 'nonanswer5': 1,})

and

I have all your Logging But this should work: 

  if opt_dict: value in opt_dict.items () for the key: If the key "nonanswer": Print "Answer", print the "Answer" key in Alif : Print "Answer", Other Value: Increase exception ("Invalid key") Other: Print "blank word"

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